/*Write a program in C to print the following series's sum*/
// Series: 1+(2/1!)+(3/2!)+(4/3!)+.....(n/n-1!)=sum

#include<stdio.h>
int main ()
{
	int n, i, j, fact;
	float term, sum=1.0;
	printf ("\nEnter the limit or last digit (only numberator's') of series: ");
	scanf ("%d", &n);
	for (i=2; i<=n; i++)
	{
		fact = 1; //intialising fact here gives correct output
		for (j=1; j<i; j++)
		{
			fact = fact * j;
		}
		term = (float) i / fact; //if we put (i / fact) it gives wrong output
		sum = sum + term;
	}
	printf ("The sum of the series: %f", sum);
	return 0;
}